when heard independently two sound waves produce sensations of 60 DB and 55 DB how much will the sensation be if those face sounded together perfectly in the phase
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Answered by
10
Answer:
The formula for Intensity and Measurement in Decibels is
Measurement in Decibels = 10 log Intensity / 10^-12 W/m^2
So,
if
Decibel measurement is 60
This means that
Intensity will be = 10^-6
And similarly for Decibel measurements in 55 Db will be
Intensity = 1/√10 * 10^-6
So,
net intensity when the two waves are in phase will be
Inet = (√I1 + √I2)^2 = 10^-6 * ( 1+ 1/√√10)^2
= 10^-6 * ( 1+ 1/10^1/4)^2
Using binomial theorem and neglecting higher powers
Net intensity = 10^-6 * (1+2(1/10)^1/4)
= 10^-6 (2.22)
So, finally
Decibel measurement = 10 log 2.22 10^-6/10^-12
= 10 log 2.22 * 10^6 = 63.463 Decibels.
Hope this helps you !
Answered by
0
Explanation:
State and prove Gauss'law
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