Question

When heat energy of 1500 Joules, is supplied to a gas at constant pressure 2.1 × 105 N/m2, there was an increase in its volume equal to 2.5 × 10–3 m3. The increase in internal energy of the gas in Joules is​

Answer 1

Answer:

Change in internal energy = Heat energy added + work done

ΔU=1500−(2.1×10

5

)×(2.5×10

−3

)

ΔU=1500−525=975J