When heating PCI, then it decompose PCl, and
Cl, in form of gas, The vapour density of gas
mixture is 70.2 and 57.9 at 200° C and 250°C.
The degree of dissociation of PCl, at 200°C and
250°C is
(1) 48.50% & 80% (2) 60% & 70%
(3) 70% & 80% 6 (4) 80% & 90%
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Answer:
48.50% and 80%
We know that when PCl5 is heated it decomposes to give PCl
3
and Cl
2
PCl
5
→PCl
3
+Cl
2
Given,
The vapour density at equilibrium at 200
0
C and 250 C.The initial Vapour Density at both the temperature MPCl5/2
therefore,initial V.D.=(31+5×35.5)/2=104.5
V..D. at equilibrium at 200
0
C=70.2(given)
total moles initial
total mole at equilibrium
=1+α=
V.D. at equilibrium
initial V.D.
1+α=
70.2
104.5
=1.485
α=0.485
∴%α=48.5%
At 250
ο
C
1+α=
57.9
104.25
=1.8
α=0.80
∴%α=80%
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