Physics, asked by abhinandanvv2503, 1 year ago

When hooks are formed in deformed bars the internal radius of the bend should be atleast

Answers

Answered by mayank0749
2
Generally 9 times of diameter used for hook.
For Mild steel twice the diameter.For Cold worked steel four times the diameter.The radius of hook= n$ . 
Where $=Dia of bar.
n=2 for plain mild steel bar.
n=4 for HYSD bar.
So radius of hook= 2$. So option is correct.Internal radius of the bend is thrice the diameter and the length of straight bar beyond the end of curve should be least four time the diameter of the bar.

Ref. R. S. KHURMI (PAGE - 527).
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