Question

When hydrogen atom emits a photon of energy 12.09ev its orbital angular momentum changes by????

Answer 1

Answer:

The formula for change in angular momentum is:

=(n2−n1)h2π

Solution:

When the hydrogen atom emits a photon of 12.09eV, it corresponds to the transition from n = 3 to n = 1.

Thus Calculation for change in momentum:

= (n2−n1) h2π

= (3−1) h2π

= hπ

= 6.626×10−343.14

= 2.11×10−34 JouleSecond (Js).

So the change in energy is 2.11×10−34 JouleSecond when hydrogen atom emits a photon of 12.09eV