) When hydrogen gas is passed over copper oxide, we get copper and water
vapour. Write the equation for the given reaction. Also identify the
substance oxidised, substance reduced, oxidising agent and reducing agent.
Answers
Explanation:
When Hydrogen gas is passed over the heated copper oxide, both steam and copper are formed. The balanced chemical equation with the physical state for this reaction is given below. Cu O (s) + H2 (g) ===> heat ==> Cu (s) + H2O (g). n this process, Hydrogen is oxidized and Cu is reduced.
Explanation:
CuO + H2 → Cu + H2O is a oxidation-reduction reaction (redox). One element gets oxidized and the other gets reduced. This occurs because the oxidation state of the elements changes as a result of the reaction. Cu in CuO has a oxidation state of 2+ and oxygen in CuO has a oxidation state of 2-. All elements in their elemental state have an oxidation state of 0. So elemental hydrogen and copper have oxidation states of 0. The hydrogen in water has an oxidation state of 1+ and oxygen again has a oxidation state of 2-. The Cu goes from an oxidation state of 2+ as a reactant to a state of 0 as a product. Hydrogen goes from an oxidation state of 0 as a reactant to a state of 1+ as a product. Copper has gained 2 electrons and each hydrogen atom has lost 1 electron. Oxidation is loss of electrons and reduction is gain of electrons (OILRIG), so copper has been reduced and hydrogen has been oxidized. The copper acted as an oxidizing agent for the hydrogen and hydrogen acted as a reducing agent for the copper.
CuO + H2 → Cu + H2O is a oxidation-reduction reaction (redox). One element gets oxidized and the other gets reduced. This occurs because the oxidation state of the elements changes as a result of the reaction. Cu in CuO has a oxidation state of 2+ and oxygen in CuO has a oxidation state of 2-. All elements in their elemental state have an oxidation state of 0. So elemental hydrogen and copper have oxidation states of 0. The hydrogen in water has an oxidation state of 1+ and oxygen again has a oxidation state of 2-. The Cu goes from an oxidation state of 2+ as a reactant to a state of 0 as a product. Hydrogen goes from an oxidation state of 0 as a reactant to a state of 1+ as a product. Copper has gained 2 electrons and each hydrogen atom has lost 1 electron. Oxidation is loss of electrons and reduction is gain of electrons (OILRIG), so copper has been reduced and hydrogen has been oxidized. The copper acted as an oxidizing agent for the hydrogen and hydrogen acted as a reducing agent for the copper.Copper is the oxidizing agent.