when hypotenuse is 13 find the base and height
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Answer:
AB
2
+BC
2
=AC
2
(By pythagoras theorem)
⟹(x−7)
2
+x
2
=13
2
⟹x
2
+x
2
+49−14x=169
⟹2x
2
−14x+(49−169)=0
⟹2x
2
−14x−120=0
⟹x
2
−7x−
2
120
=0
⟹x
2
−7x−60=0
⟹x
2
−12x+5x−60=0
⟹x(x−12)+5(x−12)=0
⟹(x−12)(x+5)=0
∴x=12 (x=-5 is not possible since side can't be negative)
∴Base=12cm
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