Question

when i chhoose 1 img then then data in console is Content-Disposition: form-data; name="0"; filename="paris.jpg" and if io choose 2 images then data is :- Content-Disposition: form-data; name="0"; filename="paris.jpg" Content-Disposition: form-data; name="1"; filename="france.jpg" and if 3 files:- Content-Disposition: form-data; name="0"; filename="paris.jpg" Content-Disposition: form-data; name="1"; filename="france.jpg" Content-Disposition: form-data; name="2"; filename="india.jpg" and so on... that means input type file name is increasing how can i move all the files i choose how to fetch file names with increasing images choosed $filename = $_FILES['0'] $filename = $_FILES['1'] and so on..

Answer 1

Answer:

1. First go to file details
2. then open the file
3. then rename it .
4. and over your problem solved

Answer 2

Answer:

Choose file and save thier