Question

when initial concentration of the reactant is doubled the rate of the reaction gets doubled what will be the order of the reaction ​

Answer 1

r= k [a]^x

2r= k[2a]^x

now spilt 2a^x into( 2^x) * (a^x)

2r= k[a^x]* [2^x]

2r= r* [2^x]

2= 2^x

x=1

so it is first order reaction.