when iron (ll) sulphate is treated with sodium hydroxide solution, the colour of precipite is
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Answer:
Iron(ll) ions Fe 2+
react with sodium hydroxide to form green coloured precipitates of iron(ll) hydroxide.
Fe 2+ +2OH − →Fe(OH) 2 (s)
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When iron (II ) sulphate is treated with sodium hydroxide you will get a colourless solution of Na2So4 and a green precipitate of Fe(OH)2
FeSo4 + NaOH------- Fe(OH)2 + Na2So4
(green precipitate) (colorless)
Balancing equation:--
FeSo4 + 2NaOH-------Fe (OH)2 + Na2So4
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