Math, asked by johnpriyansu, 3 months ago

when iron (ll) sulphate is treated with sodium hydroxide solution, the colour of precipite is​

Answers

Answered by swathi21025
0

Answer:

Iron(ll) ions Fe 2+

react with sodium hydroxide to form green coloured precipitates of iron(ll) hydroxide.

Fe 2+ +2OH − →Fe(OH) 2 (s)

Answered by rucchujj21
1

When iron (II ) sulphate is treated with sodium hydroxide you will get a colourless solution of Na2So4 and a green precipitate of Fe(OH)2

FeSo4 + NaOH------- Fe(OH)2 + Na2So4

(green precipitate) (colorless)

Balancing equation:--

FeSo4 + 2NaOH-------Fe (OH)2 + Na2So4

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