when is an equation called an identity .prove that 1+tan²A=sec²A
Answers
Answered by
2
By Pythagorean Theorem,
Hence ,
sin2x + cos2x = 1
Proof : tan²A + 1 = sec²A
From ,sin²A + cos²A = 1
sin²A/cos²A + cos²A/cos²A = 1/cos²A
(sin A/cos A)² + 1 = (1/cos A)²
tan²A + 1 = sec²A
hence proved
Proof f: 1 + cot2x = csc2x
sin²A/sin²A + cos²A/sin²A = 1/sin²A
by squared on both sides,
(cos A/sin A)² + 1 = (1/sin A)²
1 + cot2x = csc2x
Similar questions