Question

when is screw gauge of least count 0.01 mm is used to measure the diameter of a wire the reading on the sleeve is found to be 1 mm in the reading on thimble is found to be 27 divisions what is the diameter of the wire in centimetre if the zero error is + 0.005 what is the correct diameter​

Answer 1

Answer:

Diameter of the wire is 1.265 mm

Explanation:

Total reading = reading on the sleeve + reading on the thimble

Reading on the sleeve = 1 mm

Reading on the thimble :

Given the least count as 0.01 mm it means :

1 division = 0.01 mm

The reading on the thimble scale is therefore = 27 × 0.01 =0.27mm

Total reading = 1 mm + 0.27 mm

= 1.27 mm

However we have a zero error of + 0.005 mm.

This means the scale begins at 0.005 mm and not 0.

The correct reading is therefore :

= 1.27mm - 0.005 mm = 1.265 mm

The correct diameter of the wire = 1.265 mm

Answer 2

Answer:

diameter of the wire = 0.127 cm

correct diameter = 0.122 cm

Explanation:

given, L.C. = 0.01mm

n = 27

M.S.R = 1 mm

Diameter of the wire = M.S.R + C.S.R

1 + n × L.C

1 + 27 × 0.001

1 × 0.27 = 1.27 mm

0.127 cm

correct diameter = observed diameter - zero error

0.127 - (+0.005)

0.122 cm