Question

When is stoichiometry coefficient equal to x in rate law exp?

Answer 1

$\darkorange{Hola\: Mate!}$

For reaction 2A⟶B (elementary step), according to the rate law, rate =k[A]2.

In some calculations, we use k[A]2 as the production rate of B. Why isn't it 12k[A]2?

In this case, is the consumption rate of A also k[A]2? If so, why are they the same when in fact two molecules of A produce one molecule of B?

I'm really confused about this part. Can anyone explain why coefficient doesn't play a role in this calculation? Thanks!