when isosceles triangle ABC with ab is equal to AC D and e are points on BC such that BD is equal to AC
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Step-by-step explanation:
Given :- A triangle ABC in which AB=AC. D and E are points on BC such that BE = CD.
To prove :- AD= AE.
proof :- BE=CD
= BE-DE = CD-DE
= BD = CE
NOW IN TRIANGLE ABD AND TRIANGLE ACE,
AB=AC
ANGLE B = ANGLE C
BD = CE
BY SAS CRITERIA, TRIANGLE ABD CONGRUENT TO TRIANGLE ACE.
BY CPCT, AD = DE
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