Question

when it is heated from 27°C
20. Volume of the air that will be expelled from a vessel of 300 cm
37°C at the same pressure will be:
(a) 310 cm3 (b) 290 cm
(c) 10 cm3
(d) 37 cm

Answer 1

Answer:

c is the correct answer of this question

Answer 2

Answer:

The volume of air that is expelled from a vessel is 10 $cm^3$.

Explanation:

Given:

$V_1$= Volume of the vessel = 300 $cm^3$

$T_1$= Initial Temperature = 27°C = 300 K

$T_2$= Final Temperature = 37°C = 310 K

To find: The gas expelled from the container

Formula: According to Charles’ Law, $\frac{\mathrm{v}_{1}}{\mathrm{T}_{1}}=\frac{\mathrm{v}_{2}}{\mathrm{T}_{2}}$

Calculation: From formula,

$\frac{\mathrm{v}_{1} \times \mathrm{T}_{2}}{\mathrm{T}_{1}}=\mathrm{V}_{2}$

By substituting values in the formula, we obtain,

$V_2$$=\frac{300 \times 310}{300}$  

$V_2$=310 $cm^3$  

The volume of the gas expelled from the vessel =$V_2-V_1$

=310-300=10 $cm^3$