Question

when k2cr2O7 is converted into k2cr04 the change in oxidation number of cr is

Answer 1

Answer:

Concept:

The potential charge an atom would have if every one of its links to other atoms were fully ionic is known as the oxidation state, also known as the oxidation number. It describes how much an atom in a chemical molecule has been oxidised. The oxidation state might theoretically be positive, negative, or zero. Although nature does not include entirely ionic bonds, it does contain numerous strong ionic bonds, making the oxidation state a reasonable predictor of charge. A chemical process that results in an increase in an atom's oxidation state is known as oxidation; one that results in a drop in oxidation state is known as reduction. These reactions include the formal transfer of electrons; a reduction is an increase in electrons, while an oxidation is a decrease in electrons. The oxidation state of pure elements is zero.

Explanation:

• Oxidation is a chemical reaction that results in an increase in an atom's oxidation state, whereas reduction is a reaction that results in a decrease in oxidation state.
• A reduction is a rise in electrons, whereas an oxidation is a loss in electrons, and these reactions include the formal transfer of electrons. Pure elements are in a state of zero oxidation.

•               The potassium value will be 1 and oxygen value will be -2. Assume Chromium $x$

• $K_{2}Cr_{2}O_{7}$

            + 1×(2) + 2 × $x$ + 7 × (-2) =0

              $x$ = 6

• $K_{2}Cr_{}O_{4}$

                2 × (+1) + $x$ + 4 × (-2) = 0

                 $x$ = 6

• ∴ Chromium = +6 - (+6)

                      = 6 - 6

                         =0

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