Question

When k2cr2o7 is converted into k2cro4 the change in oxidation number of chromium is

Answer 1

the change in oxidation no of chromium is 0

Answer 2

Answer: There is no change in the oxidation state of chromium.

Explanation:

When $K_{2}Cr_{2}O_{7}$ is converted into $K_{2}CrO_{4}$ then the change in oxidation number of chromium is zero.

In case of $K_{2}Cr_{2}O_{7}$

• K has charge +1.
• Cr has charge x.
• O has charge -2.

The charge on this whole molecule is 0. Therefore, the oxidation number of Cr is calculated as follows.

                             2 + 2x - 14 = 0

                                      x = 6

In case of $K_{2}CrO_{4}$

• K has charge +1.
• Cr has charge x.
• O has charge -2.

The charge on this whole molecule is 0. Therefore, the oxidation number of Cr is calculated as follows.

                            2 + x - 8 = 0

                                  x = 6

Thus, it can be concluded that there is no change in the oxidation state of chromium.