Question

when kx cube minus 3 X square + 2 k x minus 5 is divided by X + 3 it leaves a remainder 11 find the value of k​

Answer 1

Answer:

k=-1.30

Step-by-step explanation:

x+3 is a root of the given equation so x=-3

since there is a remainder 11 so we subtract it from the equation and then put the value of x.

kx^3-3x^2+2kx-5-11

=kx^3-3x^2+2kx-16

=k(-3)^3-3(-3)^2+2k(-3)-16

=-27k-27-6k-16=0

=-33k-43=0

=k=-43/33=-1.30.

hope it helps you thanks