Question

when लाइट ट्रैवल फ्रॉम एयर इनटू वॉटर द करेक्ट path इज with diagram​

Answer 1

Answer (c). Water has a greater index of refraction than air. In passing from one of these media into the other, light will be refracted (deviated in direction) unless the angle of incidence is zero (in which case, the angle of refraction is also zero). Because the angle of refraction can be zero only if the angle of incidence is zero, ray B cannot be correct. In refraction, the incident ray and the refracted ray are never on the same side of the line normal to the surface at the point of contact, so ray A cannot be correct. Also in refraction, n

2

sinθ

2

=n

1

sinθ

1

; thus, if n

2

>n

1

, then θ

2

<θ

1

: the refracted raymakes a smaller angle with the normal in the medium having the higher index of refraction. Therefore, rays D and E cannot be correct, leaving only ray C as a likely path.

Answer 2

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Explanation:

Answer Water has a greater index of refraction than air. In passing from one of these media into the other, light will be refracted (deviated in direction) unless the angle of incidence is zero (in which case, the angle of refraction is also zero). Because the angle of refraction can be zero only if the angle of incidence is zero, ray B cannot be correct. In refraction, the incident ray and the refracted ray are never on the same side of the line normal to the surface at the point of contact, so ray A cannot be correct. Also in refraction, n

2

sinθ

2

=n

1

sinθ

1

; thus, if n

2

>n

1

, then θ

2

<θ

1

⇒ the refracted raymakes a smaller angle with the normal in the medium having the higher index of refraction. Therefore, rays D and E cannot be correct, leaving only ray C as a likely path.

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