Question

when laxmi applied a force of 50 newton on an object it undergoes a displacemnt of 2m when vinitha aplien the same forceon it it displaced 3m if so which one did more work

Answer 1

Given:-

• Force ,F = 50 N

• Displacement ,s = 2 m

• Displacement ,s' = 3m

To Find:-

• Which one work more ,W

Solution:-

As we know that Work Done is defined when force acting on the object produce some displacement .

• W = Fs

Where,

W is the Work Done

F is the Force

s is the displacement

Work done by Laxmi !!

substitute the value we get

→ W = 50 × 2

→ W = 100 J -------------(1)

Therefore,work done by laxmi is 100 Joules.

And,

Work done by vinitha !!

Substitute the value we get

→ W' = 50×3

→ W' = 150 J ----------------(2)

Therefore,work done by vinitha is 150 Joules.

From Equation 1 & 2 we observe that

work done by vinitha is more .

Answer 2

Answer:

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When laxmi applied a force of 50 newton on an object it undergoes a displacement of 2m when vinitha applied the same force on it , it displaced 3m if so which one did more work?

$\\ \\ \huge\bf \bold {\underbrace{\overbrace{\underline {\underline \color{deeppink}{⚞ \: \: \: \: \: \: \: \: \: \: \: \: ❀GiVeN❀ \: \: \: \: \: \: \: \: \: \: \: ⚟ } }}}}$

• Force, (F) = 50

• Displacement by laxmi,(s) = 2

• Displacement by vinitha ,(s) = 3

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• More work done by whom?

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$\large \bigstar \ast {\underline{ \boxed{\sf \red{W=Fs }}}} \ast \bigstar$

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Laxmi's work done:-

$\red \ast \sf{W=Fs} \\ \\ \green\implies \sf {w = 50 \times 2} \\ \\ \green \implies \sf{w = 100 \:J} \\ \\ \therefore\bf{Laxmi's \:work\: done \:is\: 100 J}$

Vinitha's work done :-

$\red \ast \sf{W=Fs} \\ \\ \green\implies \sf {w = 50\times 3} \\ \\ \green \implies \sf{w = 150\:J} \\ \\ \therefore\bf{Vinitha's \:work\: done \:is\: 150 J}$

So , work done by vinitha is more then laxmi.

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• W means work done.

• F means force .

• S means displacement.