When lead nitrate reacts with potassium iodide, yellow precipitate of
PbI₂ is formed
KNO₃ is formed
Pb(NO₃)₂ is formed
PbIO₃ is formed
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A yellow precipitate of PbI2 is formed in this reaction
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Answer:
The equation for this reaction is Pb(NO3)2 + 2KI -----> PbI2 + 2KNO3.
then the yellow precipitate will be PbI₂ i
is formed
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