Question

when length of cuboid is increased by 20% and breadth of cuboid is increased by 40% and height is decreased by 10% find vol of cuboid is increased by​

Answer 1

Answer:

Let the length be l, breadth be b and height be h

So,

Volume of cuboid = lbh

Now,

As per question the length and breadth are increased by 20%

So, new length =

l +  \frac{20}{100} l = l +  \frac{1}{5} l =  \frac{6}{5} l

Similarly,

New breadth = b +  \frac{20}{100} b =  \frac{6}{5} b

Now,

New length *new breath * reduced height = previous volume.

So,

\frac{6}{5} l \times  \frac{6}{5} b \times height= lbh \\  \frac{36}{25} lb \times height = lbh \\ height =  \frac{25}{36lb}  \times lbh =   \frac{25}{36} h

Therefore, new height should be 25/36 of previous height.

Percentage of reduction = difference /initial *100

So,

Change in height = h- 25/36h = 9/36 h = 1/4 h

So,

Percentage =

(  \frac{ \frac{1}{4} h}{h}  \times 100)\% =  (\frac{1}{4}  \times 100)\% = 25\%

Therefore, height should be reduced by 25%

Step-by-step explanation:

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