Question

When light enters a material with an angle of incidence of 53° it came out with an angle of refraction of 30°. What is the refractive index of the material?

Answer 1

Answer:

☆Concept:

▪︎whenever light enters from one medium to another, its velocity get differs,due to which deviation occurs.

▪︎when light enters from rarer to denser medium its deviates towards the normal.

☆Snell's law:

$\boxed{\bf{\green{ \mu_{i}sin(i) = \mu_{r}sin(r)}}}$

▪︎$\mu_{i}$ is refractive index of incidence medium

▪︎$\mu_{r}$ is refractive index of refractive medium.

☆solution:

》angle is always measured from normal.

》$\angle{i} = 53°$ and $\angle{r} = 30°$

$\longrightarrow{\sf{ \mu_{i}sin(i) = \mu_{r}sin(r)}}$

$\longrightarrow{\sf{ 1sin(53°) = \mu_{r}sin(30°)}}$

•incident light is in air so taking $\mu_{i}$ as 1.

$\longrightarrow{\sf{ \dfrac{4}{5} = \mu_{r}\dfrac{1}{2}}}$

$\longrightarrow{\sf{ \mu_{r}=\dfrac{8}{5}}}$

$\longrightarrow{\bf{ \mu_{r}=1.6}}$

☆☆so the refractive index of material is 1.6

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♧hope it helps!♧