Question

When light of a given wavelength is incident on a metallic surface, the stopping potential for the photoelectrons is 3.2 V. If a second light source with wavelength double that of the first is used, the stopping potential drops to 0.8 V. From these data, calculate (a) the wavelength of the first radiation and (b) the work function and the cutoff frequency of the metal.
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Answer 1

Answer:

When radiation of wavelength λ is incident on a metallic surface, the stopping potential is 4.8 V. If the same surface is illuminated with radiation of double the wavelength, then the stopping potential becomes 1.6 V. Then the threshold wavelength for the surface is :

Explanation:

When a surface 1 cm thick is illuminated with light of wave length λ the stopping potential is V

0

,but when the same surface is illuminated by light of wavelength 3λ , the stopping potential is

6

V

0

. The threshold wavelength for metallic surface is