Question

When light of frequency 2v, and intensity
I illuminates a metal in a photoelectric experiment,
the stopping potential is 2 V and saturation current
is 3 mA. Now If the frequency is reduced to one-
fourth and intensity is doubled, the new stopping
potential and saturation current are respectively
[V, is the threshold frequency]
(1) 0.5 V, 6 mA (2) 0.5 V, 3 mA
(3) 2 V, 6 mA
(4) 0,0​

Answer 1

Answer:

thanxforfreepoints. d. d. di