Physics, asked by shubharao74, 8 months ago

When light of wavelength 300nm is incident on a surface, the maximum velocity of the emitted electron is V . When light of wavelength 450nm is incident on a surface, the maximum velocity of the emitted electron is V/3. Calculate the work function of the surface.

Answers

Answered by archisharana1611
1

Answer:Given: Stopping potential = Vs = 2 V, wavelength of incident light = λ = 160 nm = 160 x 10-9 m, Threshold wavelength = λo = 240 nm = 240 x 10-9 m, speed of light = c = 3 x 108 m/s, Planck's constant = h = 6.63 x 10-34 Js, Charge on electron = e = 1.6 x 10-19 C. To Find: Stopping potential = Vs =?Nov 13, 2019

Explanation:

Answered by murthypkrishna61
0

Answer:

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