When light passes from water to plastic at angle of incidence 30°, it refracts at an angle of 22°. If the index of refraction for water =1.33, calculate the index of refraction for plastic.
Answers
Answered by
0
Answer:
7. A light ray in air is incident on an air to glass boundary at an angle of 45.0 degrees and is refracted in the glass of 30.0 degrees with the normal. What is the index of refraction of the glass?
a. 2.13
b. 1.74
c. 1.23
d. 1.41
Answer: D
Use Snell's law:
ni * sine(Theta i) = nr * sine(Theta r)
where
ni=1.00 (in air), Theta i=45.0 degrees (angle in air), Theta r=30.0 degrees (in glass)
Substitute and solve for nr.
1.00 * sine(45.0 deg) = nr * sine(30.0 deg)
1.00 * sine(45.0 deg) / sine(30.0 deg) = nr
nr = 1.41
Explanation:
pls give thanks to me
Similar questions