Physics, asked by raokvnb, 1 year ago

when light rays enters a medium with refractive index n2 from medium with refractive index n1 at curved interface with radius of curvature R is given by

n2/v-n1/u=n2_n1/R?

Answers

Answered by gadakhsanket
17
Hii friend,
I think you have written incomplete question.I have seen this question in different format.

# Complete question would be-
When a light ray enters a medium with refractive index n2 from a medium with refractive index n1 at curved interface with radius of curvature r is given by n2/v - n1/u = (n2-n1)/R . Now assume that the surface is plane and rewrite the formula with suitable changes .

# Solution-
For plane surface,
Radius of curvature will be infinity.

Putting this in formula for refraction at curved surface,
n2/v - n1/u = (n2-n1)/R
n2/v - n1/u = (n2-n1)/∞
n2/v - n1/u = 0
n2/v = n1/u
v/u = n2/n1
n2/n1=v/u

Hence solved n2/n1=v/u for plain surface.

Keep asking...
Answered by Anonymous
3

Answer:

Can you give the derivation of that formula

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