when light rays enters a medium with refractive index n2 from medium with refractive index n1 at curved interface with radius of curvature R is given by
n2/v-n1/u=n2_n1/R?
Answers
Answered by
17
Hii friend,
I think you have written incomplete question.I have seen this question in different format.
# Complete question would be-
When a light ray enters a medium with refractive index n2 from a medium with refractive index n1 at curved interface with radius of curvature r is given by n2/v - n1/u = (n2-n1)/R . Now assume that the surface is plane and rewrite the formula with suitable changes .
# Solution-
For plane surface,
Radius of curvature will be infinity.
Putting this in formula for refraction at curved surface,
n2/v - n1/u = (n2-n1)/R
n2/v - n1/u = (n2-n1)/∞
n2/v - n1/u = 0
n2/v = n1/u
v/u = n2/n1
n2/n1=v/u
Hence solved n2/n1=v/u for plain surface.
Keep asking...
I think you have written incomplete question.I have seen this question in different format.
# Complete question would be-
When a light ray enters a medium with refractive index n2 from a medium with refractive index n1 at curved interface with radius of curvature r is given by n2/v - n1/u = (n2-n1)/R . Now assume that the surface is plane and rewrite the formula with suitable changes .
# Solution-
For plane surface,
Radius of curvature will be infinity.
Putting this in formula for refraction at curved surface,
n2/v - n1/u = (n2-n1)/R
n2/v - n1/u = (n2-n1)/∞
n2/v - n1/u = 0
n2/v = n1/u
v/u = n2/n1
n2/n1=v/u
Hence solved n2/n1=v/u for plain surface.
Keep asking...
Answered by
3
Answer:
Can you give the derivation of that formula
Similar questions