Question

When liquid medicine of density rho is to put in the eye, it is done with the help of a dropper. As the bulp on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When this force becomes smaller than the weight of the drop, the drop gets detached from the dropper. If r=5xx10^-4m, rho=10^3 kgm^-3, g=10ms^-2, T=0.11Nm^-1, the radius of the drop when it detaches from the dropper is approximately

Answer 1

Answer:

Just before dettaching

force due to surface tension = weight of the liquid in the drop

T(2πr)=(34πR3)ρg

substituting the values we get

R=2.0×10−3m