Question

When log 2 = 0.3010 and log 3 =0.4771
Find : log root 18

Answer 1

log √18
= log
${18}^{1 \div 2}$
= 1/2 * log(18)
= 1/2 * log(9*2)
= 1/2[log(9*2)]
= 1/2[log9 + log2]
= 1/2[log3² + log2]
= 1/2[2(log3) + log2]

Put the value of log2 and log3

= 1/2[2(0.4771) + 0.3010]
= 1/2[0.9542 + 0.3010]
= 1/2[1.2552]
= 0.6276

Answer 2

Step-by-step explanation:

log √18

= log (18)^ 1/2

= 1/2 * log(18)

= 1/2 * log(9*2)

= 1/2[log(9*2)]

= 1/2[log9 + log2]

= 1/2[log3² + log2]

= 1/2[2(log3) + log2]

1/2[2(0.4771) + 0.3010]

= 1/2[0.9542 + 0.3010]

= 1/2[1.2552]

= 0.6276