Question

When Mary is 3.00 m from the center of a merry-go-round, her tangential speed is a constant 1.88 m/s.
(a) What is her angular speed in rad/s?
(1)
b) What is the period of rotation?
(1)
(b) What is the magnitude of her linear acceleration?

Answer 1

according to question

radius=3m

v tangential=1.88

1.angular speed

v=Rw

1.88=3×w

w=300/188 rad/s

2.time period =1/f. (f =frequency)

w = 2π/f

put the values you will get you answer

3.linear acceleration =

.

a centripetal = v²/r = w²r

calculate it by yourself by putting values..

hope it helps