Biology, asked by ahtishamdar37, 3 months ago

When Mendel self-hybridised the Fı plants of genotype RrYy, in the F2 generation the
yellow and green colour segregated in the ratio
(a) 1:2:1
(b) 3:1
(c) 9:3:3:1
(d) 1:1​

Answers

Answered by lavanyasaxena395
2

Answer:

c is the correct option

have a nice day:-)

Answered by karnamvishnu5
2

HEY MATE THIS IS UR ANSWER

In a dihybrid cross, a plant with yellow colour round seeds(YYRR) is crossed to green colour wrinkled(yyrr) seeds. In the F1 generation, plant with yellow colour wrinkled seeds(YyRr) are formed. When F1 plant is subjected to self pollination, in the F2 generation 1YYRR, 2 YYRr, 2YyRR, 4YyRr, 1YYrr, 2Yyrr, 1yyRR, 2yyRr, 1yyrr are formed genotypically and 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed phenotypically. In this 12 progeny are with yellow coloured seeds, 12 progeny with round seeds 4 progeny with wrinkled seeds, 4 progeny with green seeds. The ratio between yellow and green coloured seeded progeny is 12:4 = 3:1

So, the correct option is ‘3:1’.

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