Question

When momentum of a body increases by 200%, its
KE increases by
(1) 200%
(2) 300%
(3) 400%
(4) 800%​

Answer 1

Answer:

4) 800%

Momentum,p =MV

P increases by 200%

P1= 200/100P + P = 3P

M1=1

v1=3v

increase in K.E ={1/2m(3v)^2 -1/2mv^2}

/ 1/2mv^2 x100%

= 9 - 1x100%

= 800%

Answer 2

Answer:

(4) 800% is the answer

Explanation:

Where,

P is momentum

K is the kinetic energy

m is the mass of body

v is velocity of body

Pi and Pf is the initial and final momentum of body respectively.

Ki and If is the initial and final kinetic energy of the body respectively.

P(momentum)=mass(m)×velocity(v)

Kinetic energy is the form of mechanical energy that a body has by virtue of its motion.

Kinetic energy is directly proportional to the square of momentum

explained in attachment