When momentum of a body increases by 200% its kinetic energy increases by
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Momentum,p = mv
P increases by 200%
P1 = 200/100P + P = 3P
m1 = m
v1 = 3v
Increase in K.E = {1/2m(3v)^2 - 1/2mv^2} / 1/2mv^2 x 100%
= 9 - 1 x 100%
= 800%
P increases by 200%
P1 = 200/100P + P = 3P
m1 = m
v1 = 3v
Increase in K.E = {1/2m(3v)^2 - 1/2mv^2} / 1/2mv^2 x 100%
= 9 - 1 x 100%
= 800%
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