Question

When momentum of a body is increased by 200 its kinetic energy increases by?

Answer 1

Momentum,p = mv

P increases by 200%

P1 = 200/100P + P = 3P

m1 = m

v1 = 3v

Increase in K.E = {1/2m(3v)^2 - 1/2mv^2} / 1/2mv^2 x 100%

= 9 - 1 x 100%

= 800%