When momentum of body is icressed by 3 time its kinetic energy become
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By applying conservation of momentum.
m1v1=m2v2
mV=3mv
V=3v
Now,
KE=1/2×mv^2
KE'=1/2×mV^2 = 1/2× m (3v)^2
KE'= 9× 1/2× mv^2 = 9KE.
Therfore the kinetic energy becomes 9 times.
Hope it helps.
✌
m1v1=m2v2
mV=3mv
V=3v
Now,
KE=1/2×mv^2
KE'=1/2×mV^2 = 1/2× m (3v)^2
KE'= 9× 1/2× mv^2 = 9KE.
Therfore the kinetic energy becomes 9 times.
Hope it helps.
✌
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