when N÷5leaves a remainder of 2find the ones digit of N
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5
Answer:
2 and 7.
Step-by-step explanation:
Here,
When N is divided by 5, it leaves a reminder of 2.
It means N is not totally divisible by 5, but when 2 is subtracted from N it is divisible.
It means :
⇒ ( N - 2 ) is divisible by 5.
Let N - 2 = 5a
⇒ N - 2 = 5a
We know, all the factors( ∈ N ) of 5 have either 0 or 5 as at the place of it's ones digit.
So,
Ones digit of N - 2 has either 0 or 5.
N = ones digit( 0 or 5 ) + 2
N = ones digit( with 0 + 2 or 5 + 2 )
N = ones digit( 2 or 7 )
Hence the possible ones digit of N are 2 and 7.
Here, we assumed N ≠ 0
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