Question

When n+l is 5 then write the number of subshells and also find the number of electrons in the subshells. ​

Answer 1

Answer:

For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2.