Question

When N2gas is passed through water at 293k.how many moles of N2 would dissolve in 1litre of water?

Answer 1

P= 0.987 bar

K= 76.48 Kbar= 76480

As per the Henry’s law

P=Kx

x is the mole fraction

K is the henry’s law constant

P is the pressure in atm.

mole fraction of N2 = x / (x = 55.5)

Hence

0.987= 76480 * x / (x = 55.5)

x = 0.7 millimole

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