Question

When nephric filtrate moves in loop of henle from apex of medullary pyramid to its base, osmolarity changes from

a)300 to 600 mOsmol/lit

b)600 to 300 mOsmol/lit

c)300 to 1200 mOsmol/lit

d)1200 to 300 mOsmol/lit​

Answer 1

Answer:

Reabsorption in Henle's loop is minimum. However, this region plays a significant role in the maintenance of high osmolarity of medullary interstitial fluid. The descending limb of loop of Henle is permeable to water but almost impermeable to electrolytes. This concentrates the filtrate as it moves down. Thus filtrate at the base of loop is hypertonic. The ascending limb is impermeable to water but allows transport of electrolytes actively or passively. Therefore, as the concentrated filtrate pass upward, it gets diluted due to the passage of electrolytes to the medullary fluid.

Answer 2

When the nephric filtrate moves in the loop of Henle from the apex of the medullary pyramid to its base, osmolarity changes from 300 to 1200mOsmol/lit, i.e. option 'A' is correct.

• The loop of Henle is the site of the nephron where minimum reabsorption takes place.
• However, the Loop of Henle plays an important role in maintaining the osmolarity and salt balance of the kidney.
• The descending part of the Loop of Henle is more permeable to water and nearly impermeable to salt and ascending part of the Loop of Henle is more permeable to salts and nearly impermeable to water.
• So, when the filtrate moves from descending part, water moves out and the filtrate becomes hypertonic where osmolarity changes from 300 to 1200mOsmol/lit.
• And when the filtrate moves from the ascending part, salt moves out and the filtrate becomes hypotonic where osmolarity changes from 1200 to 200mOsmol/lit.
• The main purpose of doing this filtration process is to get a more dilute form of urine.

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