Chemistry, asked by sharoonaftab, 4 months ago

When nitrogen reacts with hydrogen to form ammonia, the equilibrium
murs contains 0.31 mol dm and 0.50 mol dm" of nitrogen and hydrogen
pecívely. If the K, is 0.50 mor’dm", what is the equilibrium concentration​

Answers

Answered by devidkumar40
0

Answer:

Initial mole ratio N2:H2 is 1:3

At equilibrium, 50% of N2, H2 has reacted and equilibrium pressure is P

N

2

+3H

2

→2NH

3

y3y2y

At equilibrium, 50% of each reactant reacted, the number of moles will become half.

The mole of N2=y−

2

y

The moles of H2=3y−

2

3y

THE moles of NH3=

2

2y

Total moles at equilibrium=

2

y

+

2

3y

+

2

2y

=3y

Partial pressure of H2=

Totalmoles

MolesofH2

×Totalpressure=

2

3y

×

3y

1

×P=

2

P

Explanation:

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