When numerator of a fraction is increased by 10% and denominator is decreased by 10%, the
resultant fraction is times of its square. Find the fraction.
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Answer:
Let x/y be the original fraction
x - numerator
y - denominator
Now (x + 10%x)/(y + 20%y) = 11/15
(x + (10/100)x)/(y + (20/100)y) = 11/15
(x + .1x)/(y + .2y) = 11/15
1.1x/1.2y = 11/15
By cross multiplication we get
16.5x = 13.2y
Which implies => x/y = 13.2/16.5 = 4/5
The original fraction is 4/5.
adityatiwari8586:
wrong hai
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