Question

When
object in Placed before a
convex mirror at a distance of 30
it
produces an image of magnification 1/2 where
should it be placed infront of so that magnification may be 1/3


& whow
image of images fleation
the munione so that magniftention may
be
9 p steunine neco
position of object
and
image
both.
convermunionis​

Answer 1

Answer:

first case when magnification is 1/2

-v/u=1/2

u=-2v

From mirror formula

1/30+1/15=1/f

f=10cm

Thus focal length =10cm

In second case.

-v/u=1/3

u=-3v

From mirrors formula

-1/3v+1/v=1/20

2/3v=1/10

v=20/3cm

Since, u=-3v

Therefore,u=-3*20/3

u=-20cm

Justification:-

m= -v/u

1/3=-20/3*-1/20

1/3=1/3

Therefore, the object should be placed at a distance of 20cm.