Question

When object is thrown upword it rises to height of h. How high the object in terms height when it loss 1/3 of its original K E energy.
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Answer 1

Answer:

1/3 PE + 2/3 KE = constant

Solving for the height of rise when KE has lost all its value

PE + KE = constant

PE + 0 = constant

PE = constant and at maximum value

mgh = maximum value

h = maximum height

This states that the height of rise h is at its maximum height when KE has lost all its value.

Solving for the height of rise h when KE lost 1/3 of its value

1/3 PE + 2/3 KE = constant

1/3 * mgh = 2/3 * 1/2 mv^2

1/3 * mg * h = 1/3 v^2

1/3 * h * mg = 1/3 v^2

This states that the height of rise h is equal to one-third of its maximum height h.

Answer 2

Explanation:

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