Question

When object of length 0.6 cm is kept perpendicular to principal axis at distance of 30 cm from the convex mirror of focal length 15 cm, find the position, size and nature of the image.

Answer 1

Given that,

Size of the object is 0.6 cm

Object distance is 30 cm from a convex mirror

Focal length of the convex mirror is 15 cm

To find,

The position, size and nature of the image.

Solution,

Let v is the image distance from the mirror. Using mirror's formula to find it.

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}$

Plugging all the values in above formula such that,

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}-\dfrac{1}{(-30)}\\\\v=10\ cm$

Magnification,

$m=\dfrac{-v}{u}=\dfrac{h'}{h}$

h' is size of image

$h'=\dfrac{-vh}{u}\\\\h'=\dfrac{-10\times 0.6}{-30}\\\\h'=0.2\ cm$

The formed image is virtual and erect.

Learn more,

Mirror's formula

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