Question

when object starts from rest with constant acc. then in equal interval of time ratio of distance traveled by it will be​

Answer 1

Answer:

Distance traveled (s) is given by :

s=ut+

2

1

at

2

Now, interval wise distance traveled are:

s

1

−s

0

=

2

a

(1)

2

=

2

a

s

2

−s

1

=

2

a

(2)

2

−

2

a

(1)

2

=

2

3a

s

3

−s

2

=

2

a

(3)

2

−

2

a

(2)

2

=

2

5a

Hence, its in the ratio =

2

a

:

2

3a

:

2

5a

=1:3:5