Question

When one looks at the foot and at the top of a tower from the roof of a building, the angles of elevation and depression are of 63 degree and 27 degree respectively. If the height of the building is 20 metres, find the height of the tower. (tan 63 = 2).

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Answer 1

Answer:

Step-by-step explanation:

The angle of elevation = 63°

The height of the building = 20 m

Let the distance between the foot of the tower and the building be “x” m.

Applying the trigonometry property of triangle

tan 63° = 20/x

⇒ 1.96 = 20/x

⇒ x = 20/1.96

⇒ x = 10.20 m  

The angle of depression = 27

Let ED be “h”.

Also, let the height of the tower be “[h + 20]” m.

Now, consider

tan 27° = h/10.20

⇒ 0.5 = h / 10.20

⇒ h = 10.20 * 0.5  

⇒ h = 5.1 m

Thus,  

The height of the tower is given by,

= h + 20

= 5.1 + 20

= 25.1 m

#answerwithquality #BAL

Answer 2

Answer:

Here is your answer!!

The angle of depression from the top of the tower to the roof of the building is given = 27°

From the figure:CD = AB = x = 10.20m CB = AD = 20 m

Let ED be “h”.

Also, let the height of the tower be “[h + 20]” m.

Now, consider ∆ EDC,

tan 27° = ED/CD⇒ 0.5 = h / 10.20⇒ h = 10.20 * 0.5  ⇒ h = 5.1 m

The height of the tower is given

= h + 20= 5.1 + 20= 25.1 m