Question

when one looks at the foot and the top of tower from the roof of building the angles of elevation and depression are 63 and 27 respectively if height of the building is 20m find height of tower​

Answer 1

Answer:

Step-by-step explanation:

Solution

→ tan 63° = BC/CD

→ 2 = 20/CD

→ CD = 20/2 → CD = 10 m

Now, cot(90° - ∅) = tan∅

→ cot(90° - 63)° = tan 63°

→ cot 27° = tan 63° = 2

→ cot 27° = BE/AE

→ 2 = 10/AE [Because BE = CD]

→ AE = 10/2 → AE = 5 m

Now, BC = DE = 20 m

→ AD = AE + DE

→ AD = 5 m + 20 m

→ AD = 25 m

Hence height of tower is 25 m.

Answer 2

♥️ANS➡️ 100m

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