Question

When one looks from the foot and top of a tower from the roof of a building the angles of elevation and depression are 63 degree and 27 degree respectively.If the height of building is 20 metres find the height of tower

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given : Angle of elevation = 27° , angle of depression = 63° , height of building = 20 m

To find :  height of tower

Explanation:

Here ,

$\tan 63 ^\circ = \frac{P}{B }\\\\\tan 63 ^\circ =\frac{BC}{CD}\\\\2 = \frac{20}{CD}\\\\CD = 10 m\\\\now, \\\\\cot (90-\theta)= \tan \theta \\\\\cot (90-63)= \tan 63^\circ \\\\\cot 27^\circ=\tan 63^\circ=2 \\\\\cot 27^\circ = \frac{BE}{AE}\\\\2 = \frac{10}{AE}\\\\AE = 5m \\\\BC = DE \\\\AD = AE+DE\\\\AD = 5 +20\\\\AD= 25 m$

Hence , The height of the tower is 25 m

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