when one mole of calcium carbonate reacts with HCl what volume of CO2 will be produced what is the mass of Calcium chloride formed
Answers
1 ans) 0.75 M solution of HCl = 0.75 moles of HCl in 1 L water
Number of moles of HCl in 25mL of 0.75 M solution = (0.75/1000)25 =0.019 moles
From equation it is clear that one mole CaCO3 reacts with two moles of HCl
So,
Number of moles of CaCO3 required to react with 0.019 moles of HCl = (1/2)0.019 = 0.001
Mass of 0.001 mole CaCO3 = (0.001 )(Molar mass of CaCO3) =(0.001 )( 100) = 0.1g
2 ans ) CaCO3-1 mol = 100gHCl-2 mol = 73g0.75M HCl - 0.75 moles of HCl in 1000mlIn 25ml = 0.75 ×25/1000 = 0.01875 molSince 1 mol HCl reacts with 2 mol CaCO3 0.01875molHCl = 0.01875/2 = 0.009375 mol CaCO3In grams= 0.009375 × molar mass of CaCO3= 0.9375g
3 ans) No. Of moles of HCL used = Mass× Volume÷1000= 0.75×25÷1000
=0.01875
=0.019
No.of moles of CaCO3 to react with HCL=1÷2 ×no.of moles of HCL
=1÷2×0.019÷1000
=9.5×10 to the power -3
Mass of CaCO3 = no. Of moles of CaCO3 × molar mass
= 9.5×10to the power -3 × 100
= 0.95 g